Find the measure of two complementary angles such that the larger angle is thrice that of the smaller.
x = measure of smaller angle {the larger is thrice (three times) the smaller}3x = measure of larger angle x + 3x = 90 {complementary angles add up to 90°} 4x = 90 {combined like terms} x = 22.5° {divided each side by 4} 3x = 67.5° {substituted 22.5, in for x, into 3x} smaller angle = 22.5°larger angle = 67.5° Ask the House
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